Guest Posted June 16, 2004 Share Posted June 16, 2004 Ok, I am a beginer at PHP, but have a little SQL knoweldge. I'm simply wanting to select a field from a table. The table is called 'sources' a simply 2 collums table with sources_name and sources_id. I'm wanting to print the sources_name vlaue given sources_id value. This is what I've tried: $my_query = tep_db_query("select sources_name from sources where sources_id = '6'"); <?php echo $my_query; ?> This brings back Resource id #5, which I know (via google) is because I'm missing a step in the PHP, but I can't figure it out! :( Many thanks for the help! (PS The sources contrib is #1888/, but I'm wanting to use the results in other sections of the admin.) Link to comment Share on other sites More sharing options...
OceanRanch Posted June 16, 2004 Share Posted June 16, 2004 Try this piece of code not tested and not syntax checked.... $my_query = tep_db_query("select sources_name from sources where sources_id = '6'"); while ($my_array = tep_db_fetch_array($my_query)) { $my_sources = $my_array['sources_name']; echo "got $my_sources"; }; Tom Link to comment Share on other sites More sharing options...
Guest Posted June 16, 2004 Share Posted June 16, 2004 Thank you Tom, that's working!! Link to comment Share on other sites More sharing options...
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