♥yesudo Posted February 26, 2004 Share Posted February 26, 2004 I am using this query: $customers_query_raw = "select c.customers_id, s.sources_name, c.customers_lastname, c.customers_firstname, c.customers_email_address, a.entry_country_id from " . TABLE_CUSTOMERS . " c join " . TABLE_ADDRESS_BOOK . " a join " . TABLE_SOURCES. " s join " . TABLE_CUSTOMERS_INFO. " i on s.sources_id = c.entry_source_id and i.customers_info_id = c.customers_id and c.customers_id = a.customers_id and c.customers_default_address_id = a. address_book_id " . $search . " order by i.customers_info_date_account_created desc, c.customers_lastname, c.customers_firstname"; Someone else has got this error when using it: 1064 - You have an error in your SQL syntax near 'on s.sources_id = c.entry_source_id and i.customers_info_id = c.customers_id and' at line 1 select count(*) as total from customers c join address_book a join sources s join customers_info i on s.sources_id = c.entry_source_id and i.customers_info_id = c.customers_id and c.customers_id = a.customers_id and c.customers_default_address_id = a. address_book_id Are there different versions of SQL which work on different syntax ? Your online success is Paramount. Link to comment Share on other sites More sharing options...
peterx Posted February 27, 2004 Share Posted February 27, 2004 Just use the standard inner join and where clause to filter out rows. select count(1) from TableA a, TableB b where a.id = b.fkey It will solve most simple join queries. Link to comment Share on other sites More sharing options...
♥yesudo Posted February 27, 2004 Author Share Posted February 27, 2004 Thanx Peter will try. Your online success is Paramount. Link to comment Share on other sites More sharing options...
Guest Posted April 2, 2004 Share Posted April 2, 2004 Hi, i'm getting the same error. Are you able to post the code that got it working for you? (assuming you got it working!) THANKS! Link to comment Share on other sites More sharing options...
♥yesudo Posted April 2, 2004 Author Share Posted April 2, 2004 http://www.oscommerce.com/forums/index.php?showtopic=79827&st=40 Your online success is Paramount. Link to comment Share on other sites More sharing options...
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